PUMPA - SMART LEARNING

எங்கள் ஆசிரியர்களுடன் 1-ஆன்-1 ஆலோசனை நேரத்தைப் பெறுங்கள். டாப்பர் ஆவதற்கு நாங்கள் பயிற்சி அளிப்போம்

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A TV tower stands vertically on a bank of a canal. The tower is watched from a point on the other bank directly opposite to it. The angle of elevation of the top of the tower is \(58^{\circ}\). From another point \(20 \ m\) away from this point on the line joining this point to the foot of the tower, the angle of elevation of the top of the tower is \(30^{\circ}\). Find the height of the tower and the width of the canal. (Use \(tan \ 58^{\circ} = 1.6003\))
 
Answer:
 
The height of the tower \(=\)  
 
The width of the canal \(=\)  
 
(Note: Enter the number in the first box and the unit (short form)  in the second box. Round off the answers to \(2\) decimal places.)