UPSKILL MATH PLUS
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Learn moreA TV tower stands vertically on a bank of a canal. The tower is watched from a point on the other bank directly opposite to it. The angle of elevation of the top of the tower is \(58^{\circ}\). From another point \(20 \ m\) away from this point on the line joining this point to the foot of the tower, the angle of elevation of the top of the tower is \(30^{\circ}\). Find the height of the tower and the width of the canal. (Use \(tan \ 58^{\circ} = 1.6003\))
Answer:
The height of the tower \(=\)
The width of the canal \(=\)
(Note: Enter the number in the first box and the unit (short form) in the second box. Round off the answers to \(2\) decimal places.)