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A TV tower stands vertically on a bank of a canal. The tower is watched from a point on the other bank directly opposite to it. The angle of elevation of the top of the tower is 58^{\circ}. From another point 20 \ m away from this point on the line joining this point to the foot of the tower, the angle of elevation of the top of the tower is 30^{\circ}. Find the height of the tower and the width of the canal. (Use tan \ 58^{\circ} = 1.6003)
 
Answer:
 
The height of the tower =  
 
The width of the canal =  
 
(Note: Enter the number in the first box and the unit (short form)  in the second box. Round off the answers to 2 decimal places.)