UPSKILL MATH PLUS
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Learn moreCase I: If the given times are in \(24\)-hour format, you can directly subtract those times and find the duration.
Case II: If the given times are in \(12\)-hour format, first convert them into \(24\)-hour format, and then subtract those times and find the duration.
Example:
1. Calculate the duration between \(10\!:\!40\) hours to \(16\!:\!15\) hours.
Solution:
Starting time \(=\) \(10\!:\!40\) hours
Ending time \(=\) \(16\!:\!15\) hours
Duration \(=\) Ending time \(-\) Starting time
\(=\) \(16\!:\!15\) \(-\) \(10\!:\!40\)
Here, \(40\) minutes cannot be subtracted from \(15\) minutes.
So, borrow \(1\) hour from \(16\) hours, add this to \(15\) minutes.
\(1\) hour \(+\) \(15\) minutes:
\(=\) \(60\) minutes \(+\) \(15\) minutes
\(=\) \(75\) minutes
Now, subtract \(15\!:\!75\) hours from \(10\!:\!40\) hours.
Therefore, duration between \(10\!:\!40\) hours to \(16\!:\!15\) hours is \(5\) hours \(35\) minutes.
2. Find the duration between \(11\!:\!20\) a.m. to \(5\!:\!30\) p.m.
Solution:
Let us first convert the given times to \(24\)-hour format.
Starting time \(=\) \(11\!:\!20\) a.m. \(=\) \(11\!:\!20\) hours
Ending time \(=\) \(5\!:\!30\) p.m. \(=\) \(5\!:\!30\) \(+\) \(12\!:\!00\) \(=\) \(17\!:\!30\) hours
Duration \(=\) Ending time \(-\) Starting time
\(=\) \(17\!:\!30\) hours \(-\) \(11\!:\!20\) hours
Therefore, the duration between \(11\!:\!20\) a.m. to \(5\!:\!30\) p.m. is \(6\) hours \(10\) minutes.
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