Perimeter of a rectangle — lesson. Mathematics State Board, Class 6.

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எங்கள் ஆசிரியர்களுடன் 1-ஆன்-1 ஆலோசனை நேரத்தைப் பெறுங்கள். டாப்பர் ஆவதற்கு நாங்கள் பயிற்சி அளிப்போம்

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Now, we shall find the perimeter of a rectangle.

Let us consider a rectangle

$ABCD$ whose length is

$l$

$units$ and breadth is

$b$

$units$ .

Then, the perimeter of the rectangle is given by:

Perimeter of the rectangle

$=$ Sum of the measures of all four sides

Perimeter

$P =AB+BD+DC+CA$

$units$

$P=l+b+l+b$

$units$

$P= 2l+2b$

$units$

$P=2(l+b)$

$units$

Thus, the perimeter of the rectangle is

$2(l+b)$

$units$ .

Example:

1. The length of the rectangle is

$5 \ cm$ , and breadth of the rectangle is

$3 \ cm$ . Find the perimeter of the rectangle.

Solution:

Length of the rectangle,

$l=5 \ cm$ .

Breadth of the rectangle,

$b=3 \ cm$ .

Perimeter of the rectangle

$=$ Sum of the measures of all four sides

Perimeter,

$P=2(l+b)$

Substituting the values in the formula, we have:

$P=2\times(5+3)$

$cm$

$P=2\times(8)$

$cm$

$P=16 \ cm$

Thus, the perimeter of the rectangle is

$16 \ cm$ .

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2. Perimeter of a rectangle

Theory: