Perimeter of a rectangle — lesson. Mathematics State Board, Class 6.

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Now, we shall find the perimeter of a rectangle.

Let us consider a rectangle \(ABCD\) whose length is \(l\) \(units\) and breadth is \(b\) \(units\).

Then, the perimeter of the rectangle is given by:

Perimeter of the rectangle \(=\) Sum of the measures of all four sides

Perimeter \(P =AB+BD+DC+CA\) \(units\)

\(P=l+b+l+b\) \(units\)

\(P= 2l+2b\) \(units\)

\(P=2(l+b)\) \(units\)

Thus, the perimeter of the rectangle is \(2(l+b)\) \(units\).

Example:

1. The length of the rectangle is \(5 \ cm\), and breadth of the rectangle is \(3 \ cm\). Find the perimeter of the rectangle.

Solution:

Length of the rectangle, \(l=5 \ cm\).

Breadth of the rectangle, \(b=3 \ cm\).

Perimeter of the rectangle \(=\) Sum of the measures of all four sides

Perimeter, \(P=2(l+b)\)

Substituting the values in the formula, we have:

\(P=2\times(5+3)\) \(cm\)

\(P=2\times(8)\) \(cm\)

\(P=16 \ cm\)

Thus, the perimeter of the rectangle is \(16 \ cm\).

Did you find an error?

2. Perimeter of a rectangle