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The area of the parallelogram \(ABCD\) is \(1470 \ sq. \ cm\). If \(AB = 49 \ cm\) and \(AD = 35 \ cm\) then, find the heights \(DF\) and \(BE\).
Answer:
\(DF =\) \(cm\)
\(BE =\) \(cm\)
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