Area, perimeter of parallelogram — lesson. Mathematics State Board, Class 7.

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Area:

To calculate the area of a parallelogram, we multiply the base(

$b$ ) times the height(

$h$ ).

Area of parallelogram

$A = b × h$ square units.

For example, A parallelogram has a base of

$6 m$ and height of

$3 m$ . Find its Area?

base

$(b)=6\ m$ and height

$(h) = 3\ m$ .

Area

$(A) = b \times h = 6 m \times 3 m = 18 m^{2} .$

Base:

To calculate the base of the parallelogram, we divide area

$A$ by height

$h$ .

Base of parallelogram (

$b$ )

$= A/h$ unit.

For example, A parallelogram has an area of

$64 m²$ , and is

$4 m$ height, what is its base?

Area

$(A)=64\ m^2$ and height

$(h)=4\ m$ .

Base

$(b) = \frac{A}{h} = \frac{64}{4} = 16 m .$

Height:

To calculate the height of the parallelogram, we divide the area

$A$ by base

$b$ .

Height of parallelogram (

$h$ )

$= A/b$ unit.

For example, A parallelogram has an area of

$64 m²$ and base is

$16 m$ . Find its height?

Area

$(A)=64\ m^2$ and base

$(b)=16\ m$

Height

$(h) = \frac{A}{b} = \frac{64}{16} = 4 m .$

Perimeter:

To calculate the perimeter of a parallelogram, we multiply

$2$ times the (base + side length).

Perimeter of parallelogram (

$P$ )

$= 2 (b + l)$ .

Where

$b$ is denoted as base and

$l$ is denoted as side length.

For example, A parallelogram has a base of

$5 m$ and length of

$3 m$ . Find its perimeter?

Base

$(b)=5\ m$ and side length

$(l)=3\ m$ .

Perimeter

$= 2 (b + l) = 2 (5 + 3) = 2 (8) = 16 m .$

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2. Area, perimeter of parallelogram

Theory: