10. Four mark exercise problems II

The sunshade of a window is in the form of isosceles trapezium whose parallel sides are $81 \ cm$ and $64 \ cm$ and the distance between them is $6 \ cm$. Find the cost of painting the surface at the rate of $₹2$ per $sq. \ cm$.

 

Answer:

 

Area of the sunshade of a window $=$  $sq. \ cm$

 

The cost of painting the surface $=₹$