10. Four mark exercise problems II

The sunshade of a window is in the form of isosceles trapezium whose parallel sides are \(81 \ cm\) and \(64 \ cm\) and the distance between them is \(6 \ cm\). Find the cost of painting the surface at the rate of \(₹2\) per \(sq. \ cm\).

 

Answer:

 

Area of the sunshade of a window \(=\)  \(sq. \ cm\)

 

The cost of painting the surface \(=₹\)