PUMPA - SMART LEARNING
எங்கள் ஆசிரியர்களுடன் 1-ஆன்-1 ஆலோசனை நேரத்தைப் பெறுங்கள். டாப்பர் ஆவதற்கு நாங்கள் பயிற்சி அளிப்போம்
Book Free DemoIf \(A\) is the midpoint of \(RU\) and \(T\) is the midpoint of \(RN\), prove that \(\triangle RAT \sim \triangle RUN\).
Proof:
| Statements | Reasons | |
| 1 | \(\angle ART = \angle URN\) | |
| 2 | \(RA = AU = \frac{1}{2}RU\) | |
| 3 | \(RT = TN = \frac{1}{2}RN\) | |
| 4 | \(\frac{RA}{RU} = \frac{RT}{RN} = \frac{1}{2}\) | |
| 5 | \(\triangle RAT \sim \triangle RUN\) |
Answer variants:
by ASA (1 and 4)
The sides are proportional from \(2\) and \(3\).
\(T\) is the midpoint of \(RN\)
\(\angle R\) is common in \(\triangle RAT\) and \(\triangle RUN\)
\(A\) is the midpoint of \(RU\)
The sides are proportional from \(1\) and \(2\).
by SAS (1 and 4)
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