PDF chapter test TRY NOW
In the given figure, \(D\) is the midpoint of \(OE\) and \(\angle CDE = 90^{\circ}\). Prove that \(\triangle ODC \equiv \triangle EDC\).
Proof:
| Statement | Reason | |
| 1 | \(OD = ED\) | |
| 2 | \(DC = DC\) | |
| 3 | \(\angle CDE = \angle CDO = 90^{\circ}\) | |
| 4 | \(\triangle ODC \equiv \triangle EDC\) |
Answer variants:
Given that \(D\) is the midpoint of \(OE\).
Common leg
Given that \(\angle CDE = 90^{\circ}\) and \(ODE\) is linear pair.
By SAS Criteria (1,2,3)
By RHS Criteria (1,2,3)
Register for free to see more content