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Answer variants:
(x1)(x2)
f(1)f(2)
not exactly divisible
x23x+2
(x+1)(x+2)
exactly divisible
0
f(1)=f(2)=0
Without actual division, prove that f(x) = 2x^4 - 6x^3 + 3x^2 + 3x - 2 is exactly divisible by x^2 - 3x + 2.
 
Answer:
 
f(x) = 2x^4 - 6x^3 + 3x^2 + 3x - 2
 
g(x) =
 
Simplifying g(x), we get:
 
g(x) =
 
f(1) =
 
f(2) =
 
Since
, then f(x) is 
by g(x).