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In the given figure, \(ABCD\) is a cyclic quadrilateral where diagonals intersect at \(P\) such that \(\angle DBC = 40^\circ\) and \(\angle BAC = 60^\circ\).
 
P_54 (2).png
 
Find:
 
(i) \(\angle CAD\) \(=\) \(^\circ\)
 
(ii) \(\angle BCD\) \(=\) \(^\circ\)