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In parallelogram \(ABCD\) of the accompanying diagram, line \(DP\) is drawn bisecting \(BC\) at \(N\) and meeting \(AB\) (extended) at \(P\). From vertex \(C\), line \(CQ\) is drawn bisecting side \(AD\) at \(M\) and meeting \(AB\) (extended) at \(Q\). Lines \(DP\) and \(CQ\) meet at \(O\). Show that the area of triangle \(QPO\) is \(\frac{9}{8}\) of the area of the parallelogram \(ABCD\).
 
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