21. Two marks exercise problems IX

If \(\sqrt{2} = 1.414\), \(\sqrt{3} = 1.732\), \(\sqrt{5} = 2.236\), \(\sqrt{10} = 3.162\), then find the value of the following correct to 3 places of decimals.

 

(i) \(\sqrt{40} - \sqrt{20}\) \(=\)

 

(ii) \(\sqrt{300} + \sqrt{90} - \sqrt{8}\) \(=\)

 

[Note: Enter the answer up to three decimal places]