21. Two marks exercise problems IX

If $\sqrt{2} = 1.414$, $\sqrt{3} = 1.732$, $\sqrt{5} = 2.236$, $\sqrt{10} = 3.162$, then find the value of the following correct to 3 places of decimals.

 

(i) $\sqrt{40} - \sqrt{20}$ $=$

 

(ii) $\sqrt{300} + \sqrt{90} - \sqrt{8}$ $=$

 

[Note: Enter the answer up to three decimal places]