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From the Venn diagram, verify that n(A \cup B) = n(A) + n(B) - n(A \cap B).
Proof:
LHS: n(A \cup B) =
n(A) =
n(B) =
n(A \cap B) =
RHS: n(A) + n(B) - n(A \cap B) =
Since LHS = RHS, then n(A \cup B) = n(A) + n(B) - n(A \cap B).
Hence, we proved.
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