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Answer variants:
If \(U\) \(=\) , \(X\) \(=\) and \(Y\) \(=\), then prove that \((X \cap Y)^{\prime} = X^{\prime} \cup Y^{\prime}\).
\(X \cap Y\) \(=\) , \((X \cap Y)^{\prime}\) \(=\)
\(X^{\prime}\) \(=\) , \(Y^{\prime}\) \(=\)
\(X^{\prime} \cup Y^{\prime}\) \(=\)
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