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Compute the heat generated while transferring \(96000\ coulomb\) of charge in one hour through a potential difference of \(50\ V\).
 
[Note: Enter the final answer up to one decimal place.]
 
\(t\) \(=\) \(1\ hour\)
 
On converting hour to second, we get \(t\) \(=\)  \(s\)
 
The formula of current is
 
I=ii=ii=iA
 
The formula for the amount of heat produced is
 
H=i×i×i=i×i×i=i×10iJ