Exercise XI — task. Science CBSE, Class 10.

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Show how you would connect three resistors, each of resistance $6\ Ω$ , so that the combination has a resistance of

(i) $9\ Ω$ ,

(ii) $4\ Ω$ .

$R$

$=$

$6$

$Ω$

Case (i):

If two resistors are connected in parallel, then their equivalent resistance is

$\frac{i}{\frac{i}{i} + \frac{i}{i}} = i Ω$

After connecting the third resistor, the equivalent resistance is

$Ω$ .

Case (ii):

When two resistors are connected in series, then their equivalent resistance is given by

$\begin{array}{l} R = i + i \\ = i Ω \end{array}$

The equivalent resistance is

$R = \frac{i}{i} + \frac{i}{i}$

After connecting the third resistor, the equivalent resistance is

$Ω$ .

Did you find an error?

11. Exercise XI