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A battery of \(9\ V\) is connected in series with resistors of\(0.2\ Ω\), \(0.3\ Ω\), \(0.4\ Ω\), \(0.5\ Ω\) and \(12\ Ω\), are connected in parallel in a circuit. How much current would flow through the \(12\ Ω\) resistor?
[Note: Enter the answer up to three decimal places.]
The equivalent resistance is given as
On substituting the known values, we get \(R\ =\) \(Ω\).
Using Ohm's law, we get
The current flowing across the \(12\ Ω\) resistor is \(A\).
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