Exercise VI — task. Science CBSE, Class 10.

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A copper wire has diameter $0.5\ mm$ and resistivity of $1.6 × 10^{–8} Ω m$ . What will be the length of this wire to make its resistance 10

$Ω$ ? How much does the resistance change if the diameter is doubled?

[Note: Enter the final answer up to one decimal place.]

$\rho$

$=$

$1.6 × 10^{–8} Ω m$

Diameter,

$d\ =$

$0.5\ mm$

In terms of

$metre$ , the value is .

The formula for specific resistance is

$\begin{array}{l} ρ = \frac{i i}{i} \\ i = \frac{i i}{ρ} \end{array}$

Area of cross-section of the wire is

$A = π \times {(\frac{i}{i})}^{i}$ (Write in short form)

On substituting the known values, we get the length of this wire as

$l\ =$ .

If the diameter of the wire is doubled, then the new diameter is .

On substituting the known values, the new resistance is

$R^{'}$

$=$

$Ω$

$1$

Did you find an error?

6. Exercise VI