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B_1, B_2 and B_3 are three identical bulbs connected as shown in figure. When all the three bulbs glow, a current of 3A is recorded by the ammeter A.
  
(i) What happens to the glow of the other two bulbs when the bulb B_1 gets fused?

(ii) What happens to the reading of A_1, A_2 and A_3 and A when the bulb B_2 gets fused?

(iii) How much power is dissipated in the circuit when all the three bulbs glow together?
 
12.8 (1).png
Circuit diagram
 
(i) When the bulb B_1 gets fused, the glow of the other two bulbs B_2 and B_3 .
 
(ii) Total resistance is given by
 
1R=iiR=ii
 
From Ohm's law, i=ii we get the value of resistance as  Ω.
 
When the bulb B_2 gets fused, then the total resistance is
 
1R=iiR=ii
 
The current is
 
i=ii=iA
 
Reading of A_1 =  A
 
Reading of A_2 =  A
 
Reading of A_3 =  A
 
(iii) The formula for power dissipation in the circuit is . On substituting the known values, we get .