NCERT Exemplar XXVIII — task. Science CBSE, Class 10.

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எங்கள் ஆசிரியர்களுடன் 1-ஆன்-1 ஆலோசனை நேரத்தைப் பெறுங்கள். டாப்பர் ஆவதற்கு நாங்கள் பயிற்சி அளிப்போம்

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\(B_1\), \(B_2\) and \(B_3\) are three identical bulbs connected as shown in figure. When all the three bulbs glow, a current of \(3A\) is recorded by the ammeter \(A\).

(i) What happens to the glow of the other two bulbs when the bulb \(B_1\) gets fused?

(ii) What happens to the reading of \(A_1\), \(A_2\) and \(A_3\) and \(A\) when the bulb \(B_2\) gets fused?

(iii) How much power is dissipated in the circuit when all the three bulbs glow together?

Circuit diagram

(i) When the bulb \(B_1\) gets fused, the glow of the other two bulbs \(B_2\) and \(B_3\) .

(ii) Total resistance is given by

\begin{array}{l} \frac{1}{R^{'}} = \frac{i}{i} \\ R^{'} = \frac{i}{i} \end{array}

From Ohm's law,

i = i i

we get the value of resistance as

Ω

When the bulb \(B_2\) gets fused, then the total resistance is

\begin{array}{l} \frac{1}{R} = \frac{i}{i} \\ R = \frac{i}{i} \end{array}

The current is

\begin{array}{l} i = \frac{i}{i} \\ = i A \end{array}

Reading of \(A_1\) \(=\) \(A\)

Reading of \(A_2\) \(=\) \(A\)

Reading of \(A_3\) \(=\) \(A\)

(iii) The formula for power dissipation in the circuit is . On substituting the known values, we get .

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87. NCERT Exemplar XXVIII

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