NCERT Exemplar XXXV — task. Science CBSE, Class 10.

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Find out the following in the electric circuit given in figure.

(a) Effective resistance of two \(8\ Ω\) resistors in the combination
(b) Current flowing through \(4\ Ω\) resistor
(c) Potential difference across \(4\ Ω\) resistance
(d) Power dissipated in \(4\ Ω\) resistor
(e) Difference in ammeter readings, if any.

12.9 (1).png

Circuit diagram

(a) Total resistance is given by

\begin{array}{l} \frac{1}{R_{P}} = \frac{i}{i} \\ R = i Ω \end{array}

(b) The total resistance is given by \(R\ =\)

Ω

.

From Ohm's law,

i = i i

the current flowing through the resistor is

\begin{array}{l} i = \frac{i}{i} \\ = i A \end{array}

(c) The potential difference across \(4\ Ω\) resistance is found by the formula . On substituting the known values, we get .

(d) The formula for power dissipation in the circuit is

\begin{array}{l} P = i^{i} i \\ = i W \end{array}

(e) Since it is a series circuit, the current flowing through the circuit is the . Hence, there is in the ammeter readings.

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