NCERT Exemplar XXXV — task. Science CBSE, Class 10.

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Find out the following in the electric circuit given in figure.

(a) Effective resistance of two $8\ Ω$ resistors in the combination
(b) Current flowing through $4\ Ω$ resistor
(c) Potential difference across $4\ Ω$ resistance
(d) Power dissipated in $4\ Ω$ resistor
(e) Difference in ammeter readings, if any.

12.9 (1).png

Circuit diagram

(a) Total resistance is given by

$\begin{array}{l} \frac{1}{R_{P}} = \frac{i}{i} \\ R = i Ω \end{array}$

(b) The total resistance is given by

$R\ =$

$Ω$ .

From Ohm's law,

$i = i i$ the current flowing through the resistor is

$\begin{array}{l} i = \frac{i}{i} \\ = i A \end{array}$

(c) The potential difference across

$4\ Ω$ resistance is found by the formula . On substituting the known values, we get .

(d) The formula for power dissipation in the circuit is

$\begin{array}{l} P = i^{i} i \\ = i W \end{array}$

(e) Since it is a series circuit, the current flowing through the circuit is the . Hence, there is in the ammeter readings.

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