NCERT Exemplar XXVI — task. Science CBSE, Class 10.

PUMPA - SMART LEARNING

எங்கள் ஆசிரியர்களுடன் 1-ஆன்-1 ஆலோசனை நேரத்தைப் பெறுங்கள். டாப்பர் ஆவதற்கு நாங்கள் பயிற்சி அளிப்போம்

Book Free Demo

A current of $1\ ampere$ flows in a series circuit containing an electric lamp and a conductor of $5$

$Ω$ when connected to a $10\ V$ battery. Calculate the resistance of the electric lamp. Now if a resistance of $10$

$Ω$ is connected in parallel with this series combination, what change (if any) in current flowing through $5$

$Ω$ conductor and potential difference across the lamp will take place? Give reason.

Let

$R_{1}$ be the resistance of electric lamp. Then, the total resistance is

$R = i_{i} + i$

By Ohm's law , we get the value

$R_1$ as

$Ω$ .

The resistance of the lamp is connected in series, then

$R$

$=$

$Ω$ . Then,

$\begin{array}{l} \frac{1}{R_{P}} = \frac{i}{i} \\ R = i Ω \end{array}$

The value of current is given by the formula

$I = \frac{i}{i}$

On substituting the known values, we get

$A$ .

Did you find an error?

85. NCERT Exemplar XXVI