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An electric refrigerator rated 400 \(watt\) operates 8 \(hours/day\). What is the cost of the energy to operate it for \(30\) days at \(Rs\ 3.00\ per\ kW h\)?
 
[Note: Enter the answer as a whole number.]
 
The formula for electrical energy is
 
i=i×i
 
The total energy consumed by the refrigerator in \(30\) days would be  \(Wh\). In terms of \(kWh\), it is written as .
 
Thus, the cost of energy to operate the refrigerator for \(30\) days is
 
i×i=Rsi