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Subjects
Science CBSE
Class 10
Light reflection and refraction
Textbook questions

9. Exercises IX

Exercise condition:

5 m.

An object is placed at a distance of

$10\ cm$ from a convex mirror of focal length

$15\ cm$ . Find the position and nature of the image.

Mirror formula is,

$\frac{1}{v}\ +\ \frac{1}{u}\ =\ \frac{1}{f}$
$\frac{1}{u}\ =\ \frac{1}{v}\ +\ \frac{1}{f}$
$\frac{1}{v}\ -\ \frac{1}{u}\ =\ \frac{1}{f}$
$\frac{1}{v}\ =\ \frac{1}{f}\ +\ \frac{1}{u}$

Magnification is,

$M\ =\ \frac{-u}{v}$
$M\ =\ \frac{v}{u}$
$M\ =\ \frac{-v}{u}$
$M\ =\ \frac{u}{v}$

Image distance (

$v$ )

$=$

$cm$

Magnification (

$M$ )

$=$

Nature of the image is,

real, inverted, and same size
real, inverted and diminished size
virtual, erect and diminished size
virtual, erect and same size

Important!

Note: Enter your answers with one decimal digit.

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