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Write brief answers to the following question:
Calcium chloride when dissolved in water dissociates into its ions according to the following equation.
\(CaCl_2\)(aq) → \(Ca^2{^+}\)(aq) + \(2Cl^-\)(aq)
Calculate the number of ions obtained from \(CaCl_2\) when 222 g of it is dissolved in water.
\(CaCl_2\)(aq) → \(Ca^2{^+}\)(aq) + \(2Cl^-\)(aq)
Calculate the number of ions obtained from \(CaCl_2\) when 222 g of it is dissolved in water.
1 mole of calcium chloride = .
∴ 222 g of \(CaCl_2\) is equivalent to 2 moles of \(CaCl_2\).
Since 1 formula unit \(CaCl_2\) gives 3 ions, therefore, 1 mol of \(CaCl_2\) will give of ions.
2 moles of \(CaCl_2\) would give 3 × 2 = of ions.
No. of ions = No. of moles of ions × Avogadro number.
= \(6\) × × \(10^2{^3}\).
= \(36.132\) × \(10^2{^3}\).
= × \(10^2{^4}\) ions.
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