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Answer the following question:
Which has more number of atoms, 100 grams of sodium or 100 grams of iron (given, atomic mass of Na = 23 u, Fe = 56 u)?
23 g of Na = 6.022 x 10^2{^3} atoms (1 mole).
100 g of Na = ?
= 100 x 6.022 x 10^2{^3} / 23
= 6.022 / x 10^2{^3}
= 26.182 x 10^2{^3} = x 10^2{^4} atoms
100 g of Na = ?
= 100 x 6.022 x 10^2{^3} / 23
= 6.022 / x 10^2{^3}
= 26.182 x 10^2{^3} = x 10^2{^4} atoms
56 g of Fe = 6.022 x 10^2{^3} atoms
100 g of Fe = ?
= 100 x 6.022 x 10^2{^3} / 56
= 602.2 x 10^2{^3} /
= 10.753 x 10^2{^3} = x 10^2{^4} atoms
100 g of Na contain 2.6182 x 10^2{^4} atoms.
100 g of Fe contain 1.075 x 10^2{^4} atoms.
Therefore, contains more atoms.
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