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Answer the following question:
Which has more number of atoms, 100 grams of sodium or 100 grams of iron (given, atomic mass of Na = 23 u, Fe = 56 u)?
23 g of Na = \(6.022\) x \(10^2{^3}\) atoms (1 mole).
100 g of Na = ?
= \(100\) x \(6.022\) x \(10^2{^3}\) / \(23\)
= \(6.022\) / x \(10^2{^3}\)
= \(26.182\) x \(10^2{^3}\) = x \(10^2{^4}\) atoms
100 g of Na = ?
= \(100\) x \(6.022\) x \(10^2{^3}\) / \(23\)
= \(6.022\) / x \(10^2{^3}\)
= \(26.182\) x \(10^2{^3}\) = x \(10^2{^4}\) atoms
56 g of Fe = \(6.022\) x \(10^2{^3}\) atoms
100 g of Fe = ?
= \(100\) x \(6.022\) x \(10^2{^3}\) / \(56\)
= \(602.2\) x \(10^2{^3}\) /
= \(10.753\) x \(10^2{^3}\) = x \(10^2{^4}\) atoms
100 g of Na contain \(2.6182\) x \(10^2{^4}\) atoms.
100 g of Fe contain \(1.075\) x \(10^2{^4}\) atoms.
Therefore, contains more atoms.
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