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A bullet of mass 20 \(g\) is
horizontally fired with a velocity
150 \(m\ s^{-1}\) from a pistol of mass 2 \(kg\).
What is the recoil velocity of the pistol?
Let us consider,
\(m_1\) be the mass of the bullet
\(m_2\) be the mass of the pistol
\(v_1\) be final velocity of the bullet
\(v_2\) be final velocity of the pistol
\(u\) be the initial velocities of the bullet and pistol before the collision
From the law of conservation of momentum, We know that,
Recoil velocity of the pistol \(=\) \(m\ s^{-1}\).
(Note: Enter the values up to one decimal digit)
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