Intext question VIII — task. Science CBSE, Class 9.

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Two objects of masses

$100\ g$ and

$200\ g$ are moving along the same line and direction with velocities of

$2\ m\ s^{–1}$ and

$1\ m\ s^{–1}$ , respectively. They collide and after the collision, the first object moves at a velocity of

$1.67\ m\ s^{–1}$ . Determine the velocity of the second object.

Let us consider,

$m_1$ be the mass of first object

$m_2$ be the mass of second object

$u_1$ be the initial velocity of first object before collision

$u_2$ be the initial velocity of the second object before collision

$v_1$ be the final velocity of first object after collision

$v_2$ be the final velocity of the second object after collision

From the law of conservation of momentum, We know that,

$(m_1 \times m_2)\ +\ (u_1 \times u_2)\ =\ (m_1\ +\ m_2) \times (v_1\ +\ v_2)$
$(m_1 \times u_1)\ +\ (m_2 \times u_2)\ =\ (m_1 \times v_1)\ + (m_2 \times v_2)$
$\frac{m_1 \times m_2}{u_1 \times u_2}\ =\ \frac{(m_1\ +\ m_2)}{(v_1\ +\ v_2)}$
$\frac{m_1 \times u_1}{m_2 \times u_2}\ =\ (m_1\ +\ m_2) \times (v_1\ +\ v_2)$

Velocity of the second object after the collision $=$

$m\ s^{-1}$ .

(Note: Enter your answer with three decimal places)

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38. Intext question VIII