Intext question VIII — task. Science CBSE, Class 9.

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எங்கள் ஆசிரியர்களுடன் 1-ஆன்-1 ஆலோசனை நேரத்தைப் பெறுங்கள். டாப்பர் ஆவதற்கு நாங்கள் பயிற்சி அளிப்போம்

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Two objects of masses \(100\ g\) and \(200\ g\) are moving along the same line and direction with velocities of \(2\ m\ s^{–1}\) and \(1\ m\ s^{–1}\), respectively. They collide and after the collision, the first object moves at a velocity of \(1.67\ m\ s^{–1}\). Determine the velocity of the second object.

Let us consider,

\(m_1\) be the mass of first object

\(m_2\) be the mass of second object

\(u_1\) be the initial velocity of first object before collision

\(u_2\) be the initial velocity of the second object before collision

\(v_1\) be the final velocity of first object after collision

\(v_2\) be the final velocity of the second object after collision

From the law of conservation of momentum, We know that,

\((m_1 \times m_2)\ +\ (u_1 \times u_2)\ =\ (m_1\ +\ m_2) \times (v_1\ +\ v_2) \)
\((m_1 \times u_1)\ +\ (m_2 \times u_2)\ =\ (m_1 \times v_1)\ + (m_2 \times v_2)\)
\(\frac{m_1 \times m_2}{u_1 \times u_2}\ =\ \frac{(m_1\ +\ m_2)}{(v_1\ +\ v_2)}\)
\(\frac{m_1 \times u_1}{m_2 \times u_2}\ =\ (m_1\ +\ m_2) \times (v_1\ +\ v_2)\)

Velocity of the second object after the collision \(=\) \(m\ s^{-1}\).

(Note: Enter your answer with three decimal places)

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38. Intext question VIII

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