NCERT Exemplar XIV — task. Science CBSE, Class 9.

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Using second law of motion, derive the relation between force and acceleration. A bullet of \(10\ g\) strikes a sand-bag at a speed of \(10^3\ m\ s^{-1}\) and gets embedded after travelling \(5\ cm\). Calculate

(i) the resistive force exerted by the sand on the bullet

(ii) the time taken by the bullet to come to rest.

From the Newton's second law, We know that,

\(F\ =\ m \times a\)
\(F\ =\ \frac{m}{a}\)

The formula to calculate the time (\(a\)) is,

\(t\ =\ \frac{(v-u)}{a}\)
\(t\ =\ (v-u) \times a\)

Resistive force exerted by the sand on the bullet \(=\)

i^{i}

\(N\)

(Note: Enter your answer with no decimal digits)

Time taken by the bullet to come to rest \(=\)

i^{i}

\(s\)

(Note: Enter your answer with no decimal digits)

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