Multiple choice question XLVI — task. Science CBSE, Class 9.

PDF chapter test TRY NOW

1. The gravitational force between two bodies varies with distance \(r\) as:

\(\frac{1}{r}\)
\(\frac{1}{r^2}\)
\(r\)
\(r^2\)

2. The value of G in year \(1900\) was \(6.67 \times 10^{-11}\) \(Nm^2 kg^{-2}\). They value of \(G\) in the year \(2007\) will be:

\(6.673 \times 10^{-9}\) \(Nm^2 kg^{-2}\)
\(6.673 \times 10^{-10}\) \(Nm^2 kg^{-2}\)
\(6.673 \times 10^{-2}\) \(Nm^2 kg^{-2}\)
\(6.673 \times 10^{-11}\) \(Nm^2 kg^{-2}\)

Login or Fast registration

Previous exercise

Exit to the topic

Did you find an error?

Register for free to see more content

Register for free to see more content