Multiple choice question XLIV — task. Science CBSE, Class 9.

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Two persons having mass

$50\ kg$ each, are standing such that their centre of gravities are

$1\ m$ apart. Calculate the force of gravitation between them. (Take

$G\ =\ 6.67 \times 10^{−11}\ Nm^2kg^{−2}$ , Mass of earth

$M\ =\ 6 \times 10^{24}\ kg$ , Radius of earth

$R\ =\ 6.4 \times 10^6\ m$ )

$2.67 \times 10^{-7}\ N$
$1.67 \times 10^{-7}\ N$
$1.32 \times 10^{-7}\ N$
$1.67 \times 10^{-9}\ N$

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