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Subjects
Science CBSE
Class 9
Matter in our surroundings
Textbook questions
13.
Exercises I
Exercise condition:
4
m.
Answer the following question
:
Convert the following temperatures to the Celsius scale.
(a). 293 K
(b). 470 K
Temperature in Kelvin (
K
) = Temperature in °
C
- 273
+ 293
- 293
+ 273
.
Or
Temperature in °
C
= Temperature in
K
elvin
+ 273
+ 293
- 293
- 273
.
Therefore,
(a). K
- 273 = 293
K
- 273 =
-27°C
47°C
-47°C
20°C
.
(b). K
- 273 = 470
K
- 273 =
197 °C
320°C
200 °C
290°C
.
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