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Two stones are thrown vertically upwards simultaneously with their initial velocities \(u_1\) and \(u_2\) respectively. Prove that the heights reached by them would be in the ratio of \(u_1^2 \ :\ u_2^2\)

(Assume upward acceleration is \(–g\) and downward acceleration to be \(+g\)).
 
Important!
This exercise needs to be checked manually by yourself. Write your answer in the white sheet and compare it with the given answer.