Exercises II — task. Science CBSE, Class 9.

PDF chapter test TRY NOW

Joseph jogs from one end A to the other end B of a straight \(300\ m\) road in \(2\ minutes\ 30\ seconds\) and then turns around and jogs \(100\ m\) back to point C in another \(1\ minute\). What are Joseph’s average speeds and velocities in jogging

(a) from A to B and

(b) from A to C?

The formula to calculate the average speed,

\(=\ {Total\ displacement} \times {Total\ time\ taken}\)
\(=\ \frac{Total\ displacement}{Total\ time\ taken}\)
\(=\ {Total\ distance\ travelled} \times {Total\ time\ taken}\)
\(=\ \frac{Total\ distance\ travelled}{Total\ time\ taken}\)

The formula to calculate the average velocity,

\(=\ {Total\ displacement} \times {Total\ time\ taken}\)
\(=\ \frac{Total\ distance\ travelled}{Total\ time\ taken}\)
\(=\ \frac{Total\ displacement}{Total\ time\ taken}\)
\(=\ {Total\ distance\ travelled} \times {Total\ time\ taken}\)

Joseph’s average speed from \(A\) to \(B\) \(=\) \(ms^{-1}\)

Joseph’s average velocity from \(A\) to \(B\) \(=\) \(ms^{-1}\)

Joseph’s average speed from \(A\) to \(C\) \(=\) \(ms^{-1}\)

Joseph’s average velocity from \(A\) to \(C\) \(=\) \(ms^{-1}\)

(Note: Enter your answer with 2 decimal digits)

Previous exercise

Exit to the topic

Next exercise

Send feedback

Did you find an error?

Send it to us!

2. Exercises II

Exercise condition: