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Show diagramatically the electron distributions in a sodium atom and a sodium ion and also give their atomic number.
_{11}\textrm{Na}^{22} = electrons
Hence, electron distribution =
Na - 1e^-→Na^+
Na^+ = electrons
Hence, electron distribution =
The atomic number of an element is equal to the number of in its atom. Since sodium atom and sodium ion contain the same number of , the atomic number of both is .