Exercises XI — task. Science CBSE, Class 9.

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Calculate the work required to be done to stop a car of \(1500\ kg\) moving at a velocity of \(60\ \frac{km}{h}\)?

Given:

The mass of the body (\(m\)) \(=\ 1500\ kg\)

Velocity (\(v\)) \(=\ 60\ \frac{km}{hr}\)

Convert \(\frac{km}{hr}\) into \(\frac{m}{s}\),

\(=\frac{60\times1000}{3600} \frac{m}{s}\)

Velocity in \(\frac{m}{s}\) (\(v\)) \(=\)

\frac{i}{i}

\(\frac{m}{s}\)

Formula:

\(The\ work\ required\ to\ stop\ the\ moving\ car\ =\ change\ in\ potential\ energy\)
\(The\ work\ required\ to\ stop\ the\ moving\ car\ =\ change\ in\ kinetic\ energy\)
\(The\ work\ required\ to\ stop\ the\ moving\ car\ =\ change\ in\ acceleration\)
\(The\ work\ required\ to\ stop\ the\ moving\ car\ =\ change\ in\ velocity\)

The work required to stop the moving car \(=\) \(\times10^4\ J\)

Did you find an error?

11. Exercises XI