Activity XVI — task. Science CBSE, Class 9.

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எங்கள் ஆசிரியர்களுடன் 1-ஆன்-1 ஆலோசனை நேரத்தைப் பெறுங்கள். டாப்பர் ஆவதற்கு நாங்கள் பயிற்சி அளிப்போம்

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Consider two children, say $A$ and $B$ . Let us say they weigh the same. Both start climbing up a rope separately. Both reach a height of $8$ $m$ . Let us say $A$ takes $15$ $s$ while $B$ takes $20$ $s$ to accomplish the task.

What is the work done by each?
The work done is the same. However, A has taken less time than B to do the work.
Who has done more work in a given time, say in $1\ s$ ?

The formula to calculate the work done is,

$Work\ done\ =\ \frac{Force \times displacement}{Time}$
$Work\ done\ =\ \frac{Force}{displacement}$
$Work\ done\ =\ {Force} \times {displacement}$
$Work\ done\ =\ \frac{Force \times Time}{displacement}$

Work done per unit time by the children

$A$ is children

$B$ .

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50. Activity XVI

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