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Subjects
Science CBSE
Class 9
Work and energy
Textbook questions
63.
NCERT Exemplar XIII
Exercise condition:
3
m.
A ball is dropped from a height of \(10\ m\). If the energy of the ball reduces by \(40\ %\) after striking the ground, how much high can the ball bounce back? (\(g\ =\ 10\ m s^{–2}\)).
The formula to calculate the Potential energy (\(P.E\)) is,
\(P.E\ =\ m \times g\ +\ h\)
\(P.E\ =\ m \times g\)
\(P.E\ =\ m \times \frac{g}{h}\)
\(P.E\ =\ m \times g \times h\)
Height
\(=\)
\(m\)
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