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Subjects
Science CBSE
Class 9
Work and energy
Textbook questions
63.
NCERT Exemplar XIII
Exercise condition:
3
m.
A ball is dropped from a height of
10\ m
. If the energy of the ball reduces by
40\ %
after striking the ground, how much high can the ball bounce back? (
g\ =\ 10\ m s^{–2}
).
The formula to calculate the Potential energy (
P.E
) is,
P.E\ =\ m \times g\ +\ h
P.E\ =\ m \times g
P.E\ =\ m \times \frac{g}{h}
P.E\ =\ m \times g \times h
Height
=
m
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