NCERT Exemplar XX — task. Science CBSE, Class 9.

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How is the power related to the speed at which a body can be lifted? How many kilograms will a man working at the power of \(100\ W\), be able to lift at constant speed of \(1\ m s^{-1}\) vertically? (\(g\ =\ 10\ m s^{-2}\))

The formula to calculate the Potential energy (\(E_{p}\)) is,

\(E_{p}\ =\ m \times g \times h\)
\(E_{p}\ =\ m \times \frac{g}{h}\)
\(E_{p}\ =\ m \times g\ +\ h\)
\(E_{p}\ =\ m \times g\)

The formula to calculate the Power (\(P\)) is,

\(P\ =\ E_{p} \times t\)
\(P\ =\ E_{p} \times g\)
\(P\ =\ \frac{E_{p}}{g}\)
\(P\ =\ \frac{E_{p}}{t}\)

Mass \(=\) \(kg\)

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70. NCERT Exemplar XX

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