Calculation of mass from mole and volume — lesson. Science State Board, Class 10.

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1.	Calculate the mass of \(0.3\) \(mole\) of aluminium (atomic mass of \(Al=27\)).

Data:

Given moles of aluminium \(= 0.3\) \(mole\)

Atomic mass of aluminium \(= 27\)

Formula:

\begin{array}{l} Number of moles = \frac{Mass of Al}{Atomic mass of Al} \\ Mass of Al = Number of moles \times Atomic mass of Al \end{array}

Solution:

By substituting the values to the above formula, we get,

\begin{array}{l} Mass of Al & = & 0.3 \times 27 \\ = & 8.1 g \end{array}

Hence, the mass of \(0.3\) \(mole\) of aluminium \(=8.1\) \(g\)

2.	Calculate the mass of \(2.24\) \(litre\) of \(SO_2\) gas at STP.

Data:

Given volume of \(SO_2=2.24\) \(L\)

Atomic mass of \(S=32\)

Atomic mass of \(O=16\)

Solution:

\begin{array}{l} Molecular mass of {SO}_{2} & = & 32 + (16 \times 2) \\ = & 32 + 32 \\ = & 64 \end{array}

Number of moles of {SO}_{2} = \frac{Given volume of {SO}_{2} at STP}{Molar volume of {SO}_{2} at STP}

By substituting the values in the above formula, we get,

\begin{array}{l} Number of moles of {SO}_{2} & = & \frac{2.24}{22.4} \\ = & 0.1 mole \end{array}

\begin{array}{l} Number of moles & = & \frac{Mass}{Molecular mass} \\ Mass & = & Number of moles \times Molecular mass \\ = & 0.1 \times 64 \\ = & 6.4 g \end{array}

Hence, the mass of \(2.24\) \(litre\) of \(SO_2=6.4\) \(g\)

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4. Calculation of mass from mole and volume