Calculation based on molar volume — lesson. Science State Board, Class 10.

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1.	Calculate the volume occupied by $2.5$ $moles$ of $CO_2$ at STP.

Data:

Given number of moles of

$CO_2=2.5$

Molar volume of

$CO_2$ at STP

$=22.4$

$L$

Solution:

$\begin{array}{l} Number of moles of {CO}_{2} & = & \frac{Volume of {CO}_{2} at STP}{Molar volume at STP} \\ 2.5 & = & \frac{Volume of {CO}_{2} at STP}{22.4} \\ Volume of {CO}_{2} at STP & = & 22.4 \times 2.5 \\ = & 56 L \end{array}$

Therefore, the volume occupied by

$2.5$

$mole$ of

$CO_2$ at STP

$=56$

$L$

2.	Calculate the volume occupied by $12.046\times10^{23}$ of ammonia gas molecules.

Data:

Given the number of ammonia gas molecules

$=12.046\times10^{23}$

Avogadro’s number

$=6.023\times10^{23}$

Solution:

$\begin{array}{l} Number of moles & = & \frac{Number of molecules}{Avogadro " s number} \\ = & \frac{12.046 \times 10^{23}}{6.023 \times 10^{23}} \\ = & 2 moles \end{array}$

$\begin{array}{l} Volume occupied by {NH}_{3} & = & Number of moles \times Molar volume \\ = & 2 \times 22.4 \\ = & 44.8 L \end{array}$

Therefore, the volume occupied by

$12.046\times10^{23}$ of ammonia gas molecules

$=44.8$

$L$

3.	Calculate the volume occupied by $14$ $g$ of nitrogen gas.

Data:

Given mass of nitrogen

$=14$

$g$

Atomic mass of nitrogen

$=28$

Solution:

$\begin{array}{l} Number of moles & = & \frac{Given mass of the element}{Atomic mass of the element} \\ = & \frac{14}{28} \\ = & 0.5 mole \end{array}$

$\begin{array}{l} Volume occupied by N_{2} at STP & = & No . of moles \times Molar volume \\ Mass & = & 0.5 \times 22.4 \\ = & 11.2 L \end{array}$

Therefore, the volume occupied by

$14$

$g$ of nitrogen gas

$=11.2$

$L$

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7. Calculation based on molar volume

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