
PUMPA - SMART LEARNING
எங்கள் ஆசிரியர்களுடன் 1-ஆன்-1 ஆலோசனை நேரத்தைப் பெறுங்கள். டாப்பர் ஆவதற்கு நாங்கள் பயிற்சி அளிப்போம்
Book Free Demo1. Calculate the number of atoms present in 1 gram of gold (atomic mass of Au=198).
Data:
Given mass of gold =1 g
Atomic mass of Au=198
Avogadro's number =6.023\times10^{23}
Solution:
Number of atoms of Au =
Where,
x =
y =
Therefore, the number of atoms present in 1 gram of gold = z\times10^{21} g
z =
2. Calculate the number of atoms of oxygen and carbon in 5 moles of CO_2.
Calculating number of oxygen atoms in 5 moles of CO_2:
- 1 mole of CO_2 contains 2 moles of oxygen.
- 5 moles of CO_2 contain 10 moles of oxygen.
Solution:
Number of atoms of O_2 =
Therefore, the number of atoms of oxygen in 5 moles of CO_2= x\times10^{y}
Calculating the number of carbon atoms in 5 moles of CO_2:
- 1 mole of CO_2 contains 1 moles of carbon.
- 5 moles of CO_2 contain 5 moles of carbon.
Number of atoms of C =
Therefore, the number of atoms of carbon in 5 moles of CO_2= 3.011\times10^{y}