Intext solved problem III — task. Science State Board, Class 10.

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The resistance of a wire of length 10 $m$ is 2

$Ω$ . If the area of cross section of the wire is

$2 \times 10^{- 7} m^{2}$ .

Determine its,

(i) Resistivity

(ii) Conductance, and

(iii) Conductivity.

[Note: Enter the answer up to two decimal places.]

$L$

$=$ 10

$m$

$R$

$=$ 2

$Ω$

$A = 2 \times 10^{- 7} m^{2}$

(i) The formula to calculate the resistivity of a material is

$\begin{array}{l} ρ = \frac{i i}{i} \\ = \frac{i \times i \times i^{i}}{i} \end{array}$

Resistivity,

$\rho$

$=$

$\times 10^{- 7} Ω m$

(ii) The formula to calculate the conductance of a material is

$G = \frac{i}{i}$

Conductance,

$G$

$=$

$mho$

(iii) The formula to calculate the conductivity of a material is

$= \frac{i}{i \times i^{i}}$

Conductivity,

$\sigma$

$=$

$\times 10^{7} mho m^{- 1}$

$1$

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26. Intext solved problem III