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At what height from the centre of the Earth the acceleration due to gravity will be th of its {\frac{1}{4}}^{th} value as at the Earth.
 
We know that,
Answer variants:
G
R
M
E
Acceleration due to gravity g =
\times
 / (
^2)
Where, 
G =
 
M =
 
R =
  
Let us assume,
  
Height from the centre of the Earth (R') = R + h
 
The acceleration due to gravity at that height (g') = \frac{g}{4}
 
Mass of the earth =
 
By substituting we get,
 
\frac{g}{g'}=
 
After simplification,
 
From the centre of the Earth, the object is placed at