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At what height from the centre of the Earth the acceleration due to gravity will be th of its {\frac{1}{4}}^{th} value as at the Earth.
We know that,
Answer variants:
G
R
M
E
Acceleration due to gravity g = \times / (^2)
Where,
G =
M =
R =
Let us assume,
Height from the centre of the Earth (R') = R + h
The acceleration due to gravity at that height (g') = \frac{g}{4}
Mass of the earth =
By substituting we get,
\frac{g}{g'}=
After simplification,
From the centre of the Earth, the object is placed at