Solve the given problems III — task. Science State Board, Class 10.

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A mechanic unscrews a nut by applying a force of $140$ $N$ with a spanner of length $40$ $cm$ . What should be the length of the spanner if a force of $40$ $N$ is applied to unscrew the same nut?

Given:

Case 1:

Force (

$F_{1}$ )

$=$

$140$

$N$

Distance (

$d_{1}$ )

$=$

$40$

$cm$

Case 2:

Force (

$F_{2}$ )

$=$

$40$

$N$

The formula to calculate the

$moment\ of\ the\ force$ (

$\tau$ ):

$\frac{Force\ (F)}{Distance\ (D)}$
$\frac{Distance\ (D)}{Force\ (F)}$
$Force\ (F) \times Distance\ (D)$

From the given data,

$\tau _{1}$

$\tau _{2}$

Substitute the given values,

$Distance$ (

$d_{2}$ )

$=$

$cm$

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20. Solve the given problems III

Exercise condition: