HOTS Questions I — task. Science State Board, Class 10.

PUMPA - SMART LEARNING

எங்கள் ஆசிரியர்களுடன் 1-ஆன்-1 ஆலோசனை நேரத்தைப் பெறுங்கள். டாப்பர் ஆவதற்கு நாங்கள் பயிற்சி அளிப்போம்

Book Free Demo

Mass number of a radioactive element is \(232\) and its atomic number is \(90\). When this element undergoes certain nuclear reactions, it transforms into an isotope of lead with a mass number \(208\) and an atomic number \(82\). Determine the number of alpha and beta decay that can occur.

On using the given data,

\begin{array}{l} Difference in mass number = i - i \\ = i \\ Difference in atomic number = i - i \\ = i \end{array}

On using the atomic number and mass number of \(α\) and \(β\) particles, respectively.

\begin{array}{l} Number of decays = \frac{i}{i} \\ = i \end{array}

\begin{array}{l} Δ Z = i α + i β \\ = i \end{array}

Number of \(β\) decays \(=\)

Number of \(α\) decays \(=\)

Previous exercise

Exit to the topic

Next exercise

Send feedback

Did you find an error?

Send it to us!

24. HOTS Questions I

Exercise condition: