HOTS Questions I — task. Science State Board, Class 10.

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Mass number of a radioactive element is $232$ and its atomic number is $90$ . When this element undergoes certain nuclear reactions, it transforms into an isotope of lead with a mass number $208$ and an atomic number $82$ . Determine the number of alpha and beta decay that can occur.

On using the given data,

$\begin{array}{l} Difference in mass number = i - i \\ = i \\ Difference in atomic number = i - i \\ = i \end{array}$

On using the atomic number and mass number of

$α$ and

$β$ particles, respectively.

$\begin{array}{l} Number of decays = \frac{i}{i} \\ = i \end{array}$

$\begin{array}{l} Δ Z = i α + i β \\ = i \end{array}$

Number of

$β$ decays

$=$

Number of

$α$ decays

$=$

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