Numerical problems — task. Science State Board, Class 10.

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$_{88}Ra^{226}$ experiences three $α$ - decay. Find the number of neutrons in the daughter element.

According to

$α$ decay process,

$_{88}X^{226}$

$\xrightarrow{3 \alpha\ decay}$

${}_{i}Y^{i}$

$+$

$3\ α$ decay

During

$3\ α$ decay, the atomic number decreases by

$6$ and mass number decreases by

$12$ .

Number of neutrons in the daughter element is

$\begin{array}{l} N = i - i \\ = i - i \end{array}$

Number of neutrons in the daughter element

$N$

$=$

2. A cobalt specimen emits induced radiation of $75.6$ $millicurie\ per\ second$ . Convert this disintegration into becquerel. ( $One\ curie\ =\ 3.7 \times {10^{10}} Bq$ )

[Note: Enter your answer with four decimal digits]

Based on the given data,

$\begin{array}{l} 75.6 \ millicurie = i \times 10^{- 3} \times 1 curie \\ = i \times 10^{- 3} \times i \times 10^{10} \\ = i \times 10^{7} \\ = i \times 10^{9} Bq \end{array}$

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13. Numerical problems

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