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PUMPA - SMART LEARNING

எங்கள் ஆசிரியர்களுடன் 1-ஆன்-1 ஆலோசனை நேரத்தைப் பெறுங்கள். டாப்பர் ஆவதற்கு நாங்கள் பயிற்சி அளிப்போம்

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Subjects
Science State Board
Class 10
Types of chemical reactions
Textbook questions

20. Intext Example I

Exercise condition:

6 m.

Calculate the \(pH\) of \(0.01\) \(M\) \(HNO_3\).

\([H^+] = 0.01\)

\(pH=-log_{10}[H^+]\)
\(pH=-log_{10}[OH^-]\)
\(pH=log_{10}[H^+]\)

\(pH = -log_{10}\) \([0.01]\)

\(pH = -log_{10}\) \([1\times10^{-1}]\)
\(pH = -log_{10}\) \([1\times10^{-3}]\)
\(pH = -log_{10}\) \([1\times10^{-2}]\)

\(pH = -(log_{10}1 - 1\, log_{10}10)\)
\(pH = -(log_{10}1 - 2\, log_{10}10)\)
\(pH = -(log_{10}1 - 3\, log_{10}10)\)

\(pH = 0 + 2\times\,log_{10}\,10\)
\(pH = 1 + 2\times\,log_{10}\,10\)
\(pH = 2 + 2\times\,log_{10}\,10\)

\(pH = 1 + 2\times1 = 3\)
\(pH = 0 + 2\times1 = 2\)
\(pH = 2 + 2\times1 = 4\)

Hence,

\(pH = 2\)
\(pH = 4\)
\(pH = 3\)

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