Solved Example - I — task. Science State Board, Class 8.

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The temperature of a metal ball is

$30°\ C$ . When an energy of

$3000\ J$ is supplied, its temperature raises to

$40°\ C$ . Calculate its heat capacity.

From the given data,

Temperature of Metal ball before energy supply (T1)

$=$

$30°\ C$

Temperature of Metal ball after energy supply (T2)

$=$

$40°\ C$

Energy Supplied (Q)

$=$

$3000\ J$

Formula to calculate heat capacity is,

Substitute the values,

Heat Capacity

$=$

$J K^{- 1}$

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16. Solved Example - I