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The e.m.f of a cell is 1.5 \(V\). What is the energy provided by the cell to drive 0.5 \(C\) of charge around the circuit?
[Note: Enter the answer up to three decimal places.]
\(q\) \(=\) 0.5 \(C\)
\(=\) 1.5 \(V\)
The formula of e.m.f is
The above formula can be written as
The energy given by the cell is \(J\).
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