Exercise Problems - II — task. Science State Board, Class 9.

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An athlete completes one round of a circular track of diameter 200 $m$ in 40 $s$ . What will be the distance covered and the displacement at the end of 2 $mins$ 20 $s$ ?

Solution:

From the data given,

Diameter of the circular track (

$d$ )

$=$ 200

$m$ ;

Time taken to complete one lap (

$t$ )

$=$ 40

$s$ ;

Total Time

$=$ 2

$mins$ 20

$s$ (Convert it into

$s$ )

$=$

$s$ ;

We know that the formula to calculate the circumference of the circle is,

$\frac{\pi}{r}$
$\pi \times d$
$\pi \times r$
$\frac{\pi}{d}$

Substitute the values,

Circumference of the track

$=$

$m$

$=$ Distance covered in 40

$s$

So,

Distance covered in 2

$mins$ 20

$s$

$=$

$m$

Displacement $=$

$m$

$1$

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14. Exercise Problems - II

Exercise condition: